信院政〔2015〕17號
各班級、社團：
為激發(fā)我院大學(xué)生的科研興趣，進一步提高我院大學(xué)生計算機專業(yè)知識的應(yīng)用能力，鼓勵廣大學(xué)子積極參與科學(xué)創(chuàng)新實踐活動，為學(xué)生提供一個相互學(xué)習(xí)、充分展示自己創(chuàng)新能力的平臺，特決定開展2015大學(xué)生程序設(shè)計競賽，現(xiàn)將有關(guān)事項通知如下：
一、競賽組織
主辦單位：計算機與信息工程學(xué)院
承辦單位：計算機與網(wǎng)絡(luò)科技協(xié)會
二、競賽模式和環(huán)境
競賽模式：采用ICPC競賽模式
操作系統(tǒng)：Windows
語言：C/C++、Java
開發(fā)工具：Dev C++、Eclipse、codeblock、JCreator、VC++6.0
三、參賽對象：
信息學(xué)院在校學(xué)生
四、關(guān)鍵日期
報名截止日期：2015年5月8日（以班級為統(tǒng)計單位，注明年級、專業(yè)、團隊負(fù)責(zé)人、聯(lián)系方式，通過郵件發(fā)jsjds@chzu.edu.cn）
競賽舉辦日期：2015年5月10日下午
五、競賽地點
信息樓機房
六、競賽規(guī)則
（一）參賽隊伍組成
比賽以隊為參賽單位，隊的組成不超過三名參賽隊員，每個年級專業(yè)可派≤3支代表隊。
（二）比賽開展
競賽中每隊三人擁有一臺計算機，競賽命題5題，比賽時間為3個小時。
參賽隊員可以攜帶諸如書、手冊、程序清單等參考資料。參賽隊員不能攜帶任何可用計算機處理的軟件或數(shù)據(jù)(不允許任何私人攜帶的U盤、磁盤或計算器)。
參賽隊員不能攜帶任何類型的通訊工具，包括無線電接收器、移動電話。
在競賽中，參賽隊員不得和競賽技術(shù)委員會指定工作人員以外的人交談；系統(tǒng)支持人員可以回答和系統(tǒng)相關(guān)的問題，例如解釋系統(tǒng)錯誤信息。
競賽的預(yù)定時間為3小時，但當(dāng)競賽進行一定時間后，競賽技術(shù)委員會可以因為出現(xiàn)不可預(yù)見的事件而調(diào)整比賽時間長度，一旦比賽時間長度發(fā)生改變，將會以及時并且統(tǒng)一的方式通告所有參賽隊員。
比賽過程中，選手若要上廁所，必須征得裁判批準(zhǔn)，且有裁判陪同。
（三）競賽評分
試題的解答提交裁判運行，每一次運行會被判為正確或者錯誤，判決結(jié)果會及時通知參賽隊伍。
參賽隊員有權(quán)利通過提交解釋請求，針對試題描述中的不明確或錯誤的部分提問。如果裁判確認(rèn)試題中確實存在不明確或錯誤的部分，將會通告所有參賽隊伍進行聲明或更正。
競賽裁判主要負(fù)責(zé)判定解答提交是否正確，根據(jù)正確解答的解題數(shù)目進行排名，如果多支隊伍解題數(shù)量相同，則根據(jù)總用時加上懲罰時間進行排名。總用時和懲罰時間由每道解答正確的試題的用時加上懲罰時間而成。每道試題用時將從競賽開始到試題解答被判定為正確為止，其間每一次錯誤的運行將被加罰20分鐘時間，未正確解答的試題不記時。
七、結(jié)果應(yīng)用
學(xué)院將參考比賽結(jié)果綜合考核，擇優(yōu)推薦參加安徽省程序設(shè)計大賽。
附件：賽題參考格式
計算機與信息工程學(xué)院
計算機與網(wǎng)絡(luò)科技協(xié)會
2015-5-5
賽題參考格式如下：
Problem C: Biorhythms
Some people believe that there are three cycles in a person's life that start the day he or she is born. These three cycles are the physical, emotional, and intellectual cycles, and they have periods of lengths 23, 28, and 33 days, respectively. There is one peak in each period of a cycle. At the peak of a cycle, a person performs at his or her best in the corresponding field (physical, emotional or mental). For example, if it is the mental curve, thought processes will be sharper and concentration will be easier.
Since the three cycles have different periods, the peaks of the three cycles generally occur at different times. We would like to determine when a triple peak occurs (the peaks of all three cycles occur in the same day) for any person. For each cycle, you will be given the number of days from the beginning of the current year at which one of its peaks (not necessarily the first) occurs. You will also be given a date expressed as the number of days from the beginning of the current year. You task is to determine the number of days from the given date to the next triple peak. The given date is not counted. For example, if the given date is 10 and the next triple peak occurs on day 12, the answer is 2, not 3. If a triple peak occurs on the given date, you should give the number of days to the next occurrence of a triple peak.
This problem contains multiple test cases!
The first line of a multiple input is an integer N, then a blank line followed by N input blocks. Each input block is in the format indicated in the problem description. There is a blank line between input blocks.
The output format consists of N output blocks. There is a blank line between output blocks.
Input
You will be given a number of cases. The input for each case consists of one line of four integers p, e, i, and d. The values p, e, and i are the number of days from the beginning of the current year at which the physical, emotional, and intellectual cycles peak, respectively. The value d is the given date and may be smaller than any of p, e, or i. All values are non-negative and at most 365, and you may assume that a triple peak will occur within 21252 days of the given date. The end of input is indicated by a line in which p = e = i = d = -1.
Output
For each test case, print the case number followed by a message indicating the number of days to the next triple peak, in the form:
Case 1: the next triple peak occurs in 1234 days.
Use the plural form ``days'' even if the answer is 1.
Sample Input
1
0 0 0 0
0 0 0 100
5 20 34 325
4 5 6 7
283 102 23 320
203 301 203 40
-1 -1 -1 -1
Sample Output
Case 1: the next triple peak occurs in 21252 days.
Case 2: the next triple peak occurs in 21152 days.
Case 3: the next triple peak occurs in 19575 days.
Case 4: the next triple peak occurs in 16994 days.
Case 5: the next triple peak occurs in 8910 days.
Case 6: the next triple peak occurs in 10789 days.
通訊員：；初審：；終審人：王松劼